Cafe Open-Now Check: Split Shifts and Midnight-Crossing Hours

Night Owl Cafe wants a small library function that answers one question: given a moment in time, is the cafe currently open? The requirements grow across three stages, and each stage should reuse the previous one's shape rather than becoming a separate code path. Work in Python, and assume times are always given as an hour from 0-23 and a minute from 0-59 on a 24-hour clock.

Part 1: One fixed window, every day

The cafe opens and closes at the same two times every single day, for example 7:00 to 19:00. Write is_open(hour, minute) that returns whether the cafe is open at that time of day. Out-of-range hours or minutes should raise ValueError. Decide, and apply consistently: a window is open starting at its opening minute up to but not including its closing minute.

Part 2: Only on certain weekdays

The cafe is now closed some days entirely (say it's shut Mondays), with the same single window on every day it is open. Extend the signature to is_open(day, hour, minute), where day is 0 for Monday through 6 for Sunday. A day with no window at all should simply report closed for every time on that day.

Part 3: Several shifts per day, including overnight ones

Some days now have more than one window -- for example a morning shift and a separate evening shift, with the cafe closed in between. On top of that, a late evening shift can run past midnight into the next calendar day (and a Sunday-evening shift can run into Monday morning). is_open(day, hour, minute) must handle all of this with one consistent rule, not a special case for 'wraps to tomorrow.'

Example schedule

schedule = {
    0: [(420, 660), (1020, 1410)],   # Mon: 07:00-11:00 and 17:00-23:30
    1: [(420, 660), (1020, 1410)],   # Tue: same
    2: [(420, 660), (1020, 1410)],   # Wed: same
    3: [(420, 660), (1020, 1410)],   # Thu: same
    4: [(420, 660), (1020, 1560)],   # Fri: 07:00-11:00, then 17:00 to Sat 02:00
    5: [(600, 1560)],                # Sat: 10:00 to Sun 02:00
    6: [(1200, 1500)],               # Sun: 20:00 to Mon 01:00
}

Times inside each tuple are minutes since that day's midnight, and a value above 1440 means the shift ends that many minutes into the next day.

is_open(schedule, day=0, hour=8,  minute=0)   -> True    (Monday morning shift)
is_open(schedule, day=0, hour=12, minute=0)   -> False   (between Monday's two shifts)
is_open(schedule, day=4, hour=23, minute=0)   -> True    (inside Friday's overnight shift)
is_open(schedule, day=5, hour=1,  minute=0)   -> True    (still Friday's shift, now on Saturday)
is_open(schedule, day=1, hour=11, minute=0)   -> False   (exactly the closing minute)

What this problem should cover

• A time representation that compares correctly without separate hour/minute branching
• Part 1 and Part 2 expressible as special cases of the Part 3 data shape, not separate logic
• One explicit, stated rule for the closing-minute boundary
• Correct handling of a shift that crosses midnight, including the Sunday-to-Monday case