Reverse Nodes in K-Sized Groups
ByteDanceSoftware Engineer · Technical ScreenLast updated
This problem tests your ability to manipulate linked list pointers by reversing sub-segments of a list while maintaining structural integrity.
Problem Statement
Given the head of a singly linked list and an integer k, reverse the nodes of the list k at a time, and return the modified list.
If the number of nodes is not a multiple of k, the left-out nodes at the end should remain as they are. You may not alter the values in the list's nodes; only the nodes themselves may be changed.
Function Signature
class ListNode:
def __init__(self, val=0, next=None):
self.val = val
self.next = next
def reverseKGroup(head: ListNode, k: int) -> ListNode:
pass
Constraints
- The number of nodes in the list is
n. 1 <= k <= n <= 50000 <= Node.val <= 1000
Examples
Example 1:
Input: head = [1, 2, 3, 4, 5], k = 2
Output: [2, 1, 4, 3, 5]
Explanation: The first two nodes (1, 2) are reversed, the next two (3, 4) are reversed, and the last node (5) stays as is.
Example 2:
Input: head = [1, 2, 3, 4, 5], k = 3
Output: [3, 2, 1, 4, 5]
Explanation: The first three nodes (1, 2, 3) are reversed, leaving (4, 5) untouched.
Edge Cases
k = 1: The list should remain unchanged.n < k: The entire list should remain unchanged.nis a multiple ofk.
Hints
Hint 1
Determine if there are at least k nodes remaining in the list before attempting to reverse a group.
Hint 2
Use a helper function to reverse a segment of the linked list of length k, keeping track of the previous and next pointers to stitch the segments back together.
Hint 3
Use a dummy head node to simplify the logic when the head of the list itself needs to be swapped.
Follow-up questions
- How would you modify your approach to solve this problem if the linked list was doubly linked?
- Can you implement this using a recursive approach, and what would the space complexity be compared to an iterative solution?
- What changes would be required if the groups were to be reversed only if they contain exactly k nodes (i.e., discard the remaining nodes if they are fewer than k)?
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