Determine intersection dimension of two 4D subspaces
Capital OneData Scientist · Technical ScreenLast updated
This question tests the application of the Grassmann Dimension Formula to determine the possible dimensions of the intersection of two subspaces within a larger vector space.
Problem Statement
Let V be a 7-dimensional real vector space. Suppose you have two subspaces, U and W, both of which are 4-dimensional. We are interested in the dimension of their intersection, dim(U ∩ W).
- Use the Grassmann Dimension Formula to determine the range of all possible values for
dim(U ∩ W). - Identify which values in the set {0, 1, 2, 3, 4} are theoretically impossible for this intersection.
- For each possible dimension, provide a brief description of how you would construct basis vectors for U and W to achieve that intersection dimension.
- Provide a formal proof for why any dimensions identified as "impossible" cannot occur.
Definitions
- The Grassmann Dimension Formula states:
dim(U + W) = dim(U) + dim(W) - dim(U ∩ W). - Recall that for any two subspaces U and W of a vector space V,
dim(U + W) <= dim(V).
Hints
Hint 1
Recall the Grassmann Dimension Formula: dim(U + W) = dim(U) + dim(W) - dim(U ∩ W).
Hint 2
Since U + W is a subspace of V, its dimension cannot exceed the dimension of the ambient space V (which is 7).
Hint 3
Use the constraint that dim(U + W) must be at least the dimension of the largest individual subspace (4) and at most the total dimension of the ambient space (7).
Follow-up questions
- How does the result change if V were only 6-dimensional?
- If we choose two 4-dimensional subspaces 'randomly' in a 7-dimensional space, what is the most likely dimension of their intersection?
- How would you represent these subspaces computationally using matrices, and what matrix operation would you perform to find the intersection dimension?
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